It is well known that CIW Other Certification 1D0-541 - 1D0-541 exam test is the hot exam of CIW certification. pass4line offer you all the Q&A of the 1D0-541 real test . It is the examination of the perfect combination and it will help you pass 1D0-541 exam at the first time!

The CIW Other Certification 1D0-541 Questions and Answers as well as our other CIW Other Certification 1D0-541 exam training tools are not only priced to be easy on your budget - but each one is also backed with our guarantee. pass4line guarantees that after using our Cisco certification training tools, you will be prepared to take and pass your CIW Other Certification 1D0-541 exam.

Our on-site online training experts create all of the CIW 1D0-541 exam products available through pass4line. Our main goal is to get your certified with a firm understanding of the core material. Whereas other online distributors only concern themselves with helping you obtain the paper, we strive to educate the certification candidate and better prepare them for their IT career.

　
　
Exam : CIW 1D0-541
Title : CIW v5 Database Design Specialist


1. Which three pieces of information did E.F. Codd describe as necessary to retrieve a data value from a relational database?
A. Attribute, domain, and tuple
B. Entity, relation name, and domain
C. Table name, primary key, and entity
D. Attribute, relation name, and primary key
Answer: D

2. Consider the relation shown in the exhibit. Which of the following SQL statements would properly remove all tuples for New York customers?
A. DELETE *
FROM Customers
WHERE Sales_Office = New York;
B. DELETE
FROM Customers
WHERE Sales_Office = ew York?WHERE Sales_Office = ?ew York?
C. DELETE *
FROM Customers
WHERE Sales_Office = ew York?WHERE Sales_Office = ?ew York?
D. DELETE
FROM Customers
WHERE Sales_Office NOT LIKE ew York? WHERE Sales_Office NOT LIKE ?ew York?
Answer: B

3. What is the highest normal form of the relation(s) shown in the exhibit?
A. Second normal form
B. First normal form
C. Boyce-Codd normal form
D. Third normal form
Answer: A

4. Consider the Information Engineering diagram shown in the exhibit. Which DBDL definition best describes this diagram?
A. BUILDING(Building_ID, Bldg_Name, Location, Room_Count)
Primary Key Building_ID
RESIDENT(R_ID, Room_Num, Res_Name, Building_ID)
Primary Key R_ID
B. BUILDING(Building_ID, Bldg_Name, Location, Room_Count)
Primary Key BUILDING
RESIDENT(R_ID, Room_Num, Res_Name, Building_ID)
Primary Key RESIDENT
C. BUILDING(Building_ID, Bldg_Name, Location, Room_Count)
Primary Key BUILDING
Foreign Key BUILDING(Building_ID) references RESIDENT(Building_ID)
RESIDENT(R_ID, Room_Num, Res_Name, Building_ID)
Primary Key RESIDENT
D. BUILDING(Building_ID, Bldg_Name, Location, Room_Count)
Primary Key Building_ID
RESIDENT(R_ID, Room_Num, Res_Name, Building_ID)
Primary Key R_ID
Foreign Key Building_ID references BUILDING(Building_ID)
Answer: D

5. Several SQL operations are performed by User 1 to access the Fee information for Bowling in the Act_Fee relation (shown in the exhibit). The first access returns a fee of 50. An unrelated SQL operation by another user updates the Bowling fee to 60. The second access by User 1 returns a fee of 60. What problem has occurred?
A. Rollback
B. Deadlock
C. Dirty read
D. No problem has occurred.
Answer: D

6. Consider the entity-relation (ER) diagram shown in the exhibit. When the logical database design phase is completed, which of the following is a valid DBDL description of the base relations for the ER diagram?
A. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
B. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
Foreign Key Class_Num References STUDENT
C. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
STU_CLASS(
Student_Number: integer NOT NULL
Class_Num: integer NOT NULL)
Primary Key Student_Number
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
D. STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20 NOT NULL)
Primary Key Student_Number
STU_CLASS(
Student_Number: integer NOT NULL
Class_Num: integer NOT NULL)
Primary Key Student_Number, Class_Num
CLASS(
Class_Num: integer NOT NULL
Class_Name: integer NOT NULL)
Primary Key Class_Num
Answer: D

Why choose pass4line 1D0-541 braindumps

Quality and Value for the 1D0-541 Exam
100% Guarantee to Pass Your 1D0-541 Exam
Downloadable, Interactive 1D0-541 Testing engines
Verified Answers Researched by Industry Experts
Drag and Drop questions as experienced in the Actual Exams
Practice Test Questions accompanied by exhibits
Our Practice Test Questions are backed by our 100% MONEY BACK GUARANTEE.